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Xine - issue #3 - Phile 105

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Xine
 · 7 months ago

 
/-----------------------------\
| Xine - issue #3 - Phile 105 |
\-----------------------------/



-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-
FORMATING AN EXTRA TRACK
ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú-ú
--- Written by Int13h [iKx] ---
----------------------------
- Paraguay, January '98 -



INTRODUCTION
ßßßßßßßßßßßß

The boot or multipartite viruses, due to their way of acting, require space
on disk where to move the original boot sector and the rest of virus body (in
case it ocuppies more than one sector). I've noticed that,in general, the virus
writers calculate the last sector of root directory (using values stored in
the BPB, Bios Parameter Block, in the boot sector) and allocate in that space.
Very few viruses format a new track for themselves, and as this possibility has
been always present and considering my nick is Int13h, I think it was necessary
to explain all you the purpose of my function 5h ;-)
The advantage of formatting an extra track is that u have the security that the
operating system won't overwrite the virus code, even if there is no space free
in the disk. This advantage is not present in the viruses that use the last
sector of the root directory.



TRIPLE COORDINATES
ßßßßßßßßßßßßßßßßßßß

All functions of the ROM-BIOS use the triple coordinates, so as to locate
a sector.

The triple coordinates are the following:

1.) track number
2.) head number
3.) sector number


For example, to read a sector of a diskette in drive A:, we use function 2h
of Int 13h as:

mov ax,0201h
mov cx,0001h
mov dx,0000h (xor dx,dx/sub dx,dx!)
mov bx,offset Buffer
int 13h


Now, in more detail:

AH=2, read function
AL=1, number of sectors to read
CH=0, 8 low bits of track number
CL=1, 2 high bits are the bits 8 and 9 of track number
6 low bits are the sector number
DH=0, head
DL=0, physical drive
(>=80h for hard disks)
BX= buffer where to store read data


Diskettes are divided into concentric rings that are the tracks. These tracks
have 2 sides (in diskettes), and each side represents a head. Each track is
divided into a certain number of sectors. From now on, we'll take the 3 1/2
diskettes high density as an example (1.44 Mbytes of capacity).
The outer track is the track number 0, and the inner track is track number
79. Although it's possible to format an extra track number 80. We will learn
how to do that in this tutorial.



BIOS PARAMETER BLOCK
ßßßßßßßßßßßßßßßßßßßß

We can get info from the actual diskette by looking at its BPB (BIOS parameter
block) that we discussed earlier. This area is located in the boot sector
(track 0, head 0, sector 1) and starts at offset 3 of this sector. Its fields
are:

Offset Length Description
---------------------------------------------------------------
3 8 bytes System ID
11 1 word Number of bytes per sector
13 1 byte Number of sectors per cluster
14 1 word Number of reserved sectors at beginning
16 1 byte Number of FAT copies
17 1 word Number of entries in root directory
19 1 word Total number of sectors in disk
21 1 byte Format byte (FF, FE, FD, FC)
22 1 word Number of sectors per FAT
24 1 word Number of sectors per track
26 1 word Number of heads
28 1 word Number of reserved special sectors


As we said we would work with 1.44 disks, the total number of sectors is 2880.
That is calculated, multiplying 80 tracks by 2 heads by 18 sectors per track.
80x2x18=2880. That means that offset 19d(13h) in the BPB must be 0b40h=2880d.



DISK DEVICE PARAMETER TABLE
ßßßßßßßßßßßßßßßßßßßßßßßßßßß

Diskette services provided by BIOS works by control of a disk base table or
the "disk device parameter table". This table is composed by a group of 11
bytes, which are the control parameters of the diskette. The default address
for this base table is located at f000:efc7 in ROM.
But, we will create our own table. The Int 1eh is the one that points to the
base table of the disk in use. When we create our table, we must make Int 1eh
point to it. Let's see the meaning of each byte in this base table:


01 = byte of specification 1: SRT time and head load data
02 = byte of specification 2: head load time, mode DMA
03 = wait time until disk motor if off
04 = bytes per sector: 0=128; 1=256; 2=512; 3=1024
05 = number of last sector
06 = length of the gap between sectors for read/write access
07 = length of data when there is no sector length
08 = length of gap between sector in format operations
09 = byte stored in formated sectors (0xf6 by default)
10 = head stabilization time
11 = time to put motor on


We will use the following base table for disks 3 1/2:
FD35 db 0dfh,2,25h,2,12h,01bh,0fh,06ch,0f6h,0fh,8


For disks of 5 1/4, the base table is:
FD514 db 0dfh,2,25h,2,0fh,01bh,0ffh,054h,0f6h,0fh,8



FUNCTION 5H
ßßßßßßßßßßßßß

Function 5h of interrupt 13h is used to format a track in a specified head of
a diskette. The format operation is made on an entire track. We can specify
characteristics of each sector. The following are the parameters we need to
know to use this function.

AH= 5h, function to use
AL= number of sectors to create in the track
CH= track number
CL= sector number
DH= head number
DL= drive number
ES:BX= pointer to the little table


Lets talk now about the format of the required little table. It must contain
4 bytes per sector. The meaning of each byte is:

byte 1, (C) track
byte 2, (H) head
byte 3, (R) sector
byte 4, (N) bytes per sector. 0=128, 1=256, 2=512, 3=1024


It's important to note that sector needs not to start on 1. It can start by
other number of sector, but the order of sectors must be sequential.
For example, to format track 80, head 0, starting on sector 1, the table for
8 sectors format is:

Table db 80,0,1,2 ; track 80, head 0, sector 1
db 80,0,2,2 ; Sector 2
db 80,0,3,2 ; Sector 3
db 80,0,4,2 ; Sector 4
db 80,0,5,2 ; Sector 5
db 80,0,6,2 ; Sector 6
db 80,0,7,2 ; Sector 7
db 80,0,8,2 ; Sector 8


A virus can contain that table in its code, but it would waste too much space.
The best thing to do is generate the table in the heap with a small algorithm.

Neurobasher's algorithm was 24 bytes and works this way to create the table:

mov bp,50h ; track 80
mov cl,08 ; 8 sectors
mov di,offset Tabla ; the table
mov bx,di
Generation:
mov ax,bp
stosw
mov al,cl
neg al
add al,0bh
mov ah,2 ; 512 bytes per sector
stosw
loop Generation
Table db 32 dup(0)


My algorithm is 21 bytes, and does the same:

mov di,offset Table ; Buffer where table is generated
mov cx,0201h
Fabricar_Tabla:
mov ax,0050h ; 50h=80d, new track
stosw ; head=0
mov ax,cx ; CH=02, 512 bytes per sector
stosw ;
inc cl ; next sector
cmp cx,0208h
jbe Fabricar_Tabla
Table db 32 dup(0)



GIVE ME A TRACK 80
ßßßßßßßßßßßßßßßßßßß

Now we are ready to create a place for our virus! 1.44 Mbytes diskettes have
80 tracks (0-79). We will format a track 80. The steps to do that are:

1.) Save the actual Int 1eh handler in use
2.) Set the new Int 1eh pointing to our base table
3.) Generate the sector table
4.) Call Int 13h with the required parameters
5.) Restore the previous Int 1eh

If all that was done correctly, we now must have track 80, and can use it for
our evil aims. We can access that track in any moment. We don't need to redi-
rect Int 1eh to do that.

Now let's just do it....



ú ú ú- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - >8

; fORMATTING tRACK 80 iN fLOPPY dISKS 3 1/2 oF hIGH dENSITY
.model tiny
.code
org 100h

Newtrack:
mov ax,0351eh ; Get Int 1eh handler
int 21h
mov word ptr [Vieja1eh],bx
mov word ptr [Vieja1eh+2],es

push cs
pop es ; Set ES

mov ax,251eh ; Set Int 1eh
mov dx,offset FDHD35 ; Pointing to our table
int 21h

mov di,offset Tabla ; Where table is stored
mov cx,0201h
Fabricar_Tabla:
mov ax,0050h ; 50h=80d, our track!
stosw ; Head=0
mov ax,cx ; CH=02, 512 bytes per sector
stosw
inc cl ; Next sector number
cmp cx,0208h
jbe Fabricar_Tabla

xor ax,ax ; Reset disk controller
int 13h

mov ax,0508h ; Format 8 sectors
mov bx,offset Tabla
mov cx,05001h ; Track 80, starting from sector 1
xor dx,dx ; Head 0, drive A:
int 13h

mov ax,0301h ; Write some code in that track
mov bx,100h
mov cx,5001h
sub dx,dx
int 13h ; This Int looks familiar to me!

mov ax,251eh
lds dx,dword ptr [Vieja1eh] ; Restore Int 1eh
int 21h ;

int 20h ; Exit to DOS

db 'Here I am!!!'

Vieja1eh dd 0 ; Original Int 1eh handler

; Disk Base Table
FDHD35 db 0dfh,2,025h,2,012h,01bh,0ffh,06ch,2,0fh,8

; Buffer for our sector table: 8x4=32 bytes
TABLA db 32 dup(0)

End Newtrack

8< - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -ú ú ú


Executing the program, we'll have a diskette with tracks ranging from 0 to 80.
To verify it we can write a short program that reads track 80, and we'll find
the text "Here I am!"


Let's use DEBUG:

C:\DOS>DEBUG
-a100
mov ax,0201
mov cx,5001
xor dx,dx
mov bx,200
int 13
mov ax,0201
int 13

-g

-d200 l100


and we can read the text we write there before :) Why read two times with
Int 13h? Well, on my PC sometimes when reading first time it returned me carry
flag activated and an error in AH, and reading it again caused no error. I look
for an explanation for this, and founded it on a book: according to IBM, the
motor of the disk drive spends some time in order to reach the work speed, and
Int 13h services do not wait for this speed to be reached. For that reason, IBM
recommends to execute the function 3 times before giving an error. Also it re-
commends to use the reset service (ah=0/int13h) between each attempt.



CONCLUSION
ßßßßßßßßßßß

So here it ends this small tutorial. I don't see any reason for waste this
method of formating an extra track for your virus. It's not too much code
and is very useful. If u want an example of it, u can find one of my viruses
that use it in XINE#3. Thanks a lot to my kewl friend Super/29A for his
translation of this text to English. Super: gracias mogoll¢n amigazo! If u
have any comment, u can reach me at: i13h@hotmail.com.



INT 13H / iKx


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