Issue # 18 DTACK GROUNDED Newsletter - April 1983
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DTACK GROUNDED Newsletter
· 1 year ago
... unction. You might satisfy yourself that the LOG base 10 of #1 is zero, of #10 is one, of #100 is two, etc. You can also note that the LOG base 10 of #.1 is minus one, of #.01 is minus two, etc. If we express X in exponential form and remember that the LOG (any base) of one is zero, we have: 100 = 1 * 10EXP(2); LOG(100) = 2 10 = 1 * 10EXP(1); LOG(10) = 1 1 = 1 * 10EXP(0); LOG(1) = 0 .1 = 1 * 10EXP(-1); LOG(.1) = -1 .01 = 1 * 10EXP(-2); LOG(.01) = -2 (The LOGs above are all base 10) By equation (3.6.1), LOG[EXP(X)] = X, so the value of the LOG of those numbers above are equal, by equation (3.6.15), to the LOG(1), which is zero, plus the LOG[EXP(N ...